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This chapter describes the (rnrs enums (6))
library for dealing with
enumerated values and sets of enumerated values. Enumerated values are
represented by ordinary symbols, while finite sets of enumerated values
form a separate type, known as the enumeration sets. The
enumeration sets are further partitioned into sets that share the same
universe and enumeration type. These universes and
enumeration types are created by the make-enumeration
procedure.
Each call to that procedure creates a new enumeration type.
This library interprets each enumeration set with respect to its specific universe of symbols and enumeration type. This facilitates efficient implementation of enumeration sets and enables the complement operation.
In the descriptions of the following procedures, enum-set ranges
over the enumeration sets, which are defined as the subsets of the
universes that can be defined using make-enumeration
.
symbol-list must be a list of symbols.
The make-enumeration
procedure creates a new enumeration type
whose universe consists of those symbols (in canonical order of their
first appearance in the list) and returns that universe as an
enumeration set whose universe is itself and whose enumeration type is
the newly created enumeration type.
Return the set of all symbols that comprise the universe of its argument, as an enumeration set.
Return a unary procedure that, given a symbol that is in the universe of
enum-set, returns its 0–origin index within the canonical
ordering of the symbols in the universe; given a symbol not in the
universe, the unary procedure returns #f
.
(let* ((e (make-enumeration '(red green blue))) (i (enum-set-indexer e))) (list (i 'red) (i 'green) (i 'blue) (i 'yellow))) ⇒ (0 1 2 #f)
The enum-set-indexer
procedure could be defined as follows using
the memq
procedure from the (rnrs lists (6))
library:
(define (enum-set-indexer set) (let* ((symbols (enum-set->list (enum-set-universe set))) (cardinality (length symbols))) (lambda (x) (cond ((memq x symbols) => (lambda (probe) (- cardinality (length probe)))) (else #f)))))
Return a unary procedure that, given a list of symbols that belong to the universe of enum-set, returns a subset of that universe that contains exactly the symbols in the list. The values in the list must all belong to the universe.
Return a list of the symbols that belong to its argument, in the canonical order of the universe of enum-set.
(let* ((e (make-enumeration '(red green blue))) (c (enum-set-constructor e))) (enum-set->list (c '(blue red)))) ⇒ (red blue)
The enum-set-member?
procedure returns #t
if its first
argument is an element of its second argument, #f
otherwise.
The enum-set-subset?
procedure returns #t
if the universe of
enum-set1 is a subset of the universe of enum-set2
(considered as sets of symbols) and every element of enum-set1 is
a member of enum-set2. It returns #f
otherwise.
The enum-set=?
procedure returns #t
if enum-set1 is a
subset of enum-set2 and vice versa, as determined by the
enum-set-subset?
procedure. This implies that the universes of
the two sets are equal as sets of symbols, but does not imply that they
are equal as enumeration types. Otherwise, #f
is returned.
(let* ((e (make-enumeration '(red green blue))) (c (enum-set-constructor e))) (list (enum-set-member? 'blue (c '(red blue))) (enum-set-member? 'green (c '(red blue))) (enum-set-subset? (c '(red blue)) e) (enum-set-subset? (c '(red blue)) (c '(blue red))) (enum-set-subset? (c '(red blue)) (c '(red))) (enum-set=? (c '(red blue)) (c '(blue red))))) ⇒ (#t #f #t #t #f #t)
enum-set1 and enum-set2 must be enumeration sets that have the same enumeration type.
The enum-set-union
procedure returns the union of enum-set1
and enum-set2. The enum-set-intersection
procedure
returns the intersection of enum-set1 and enum-set2. The
enum-set-difference
procedure returns the difference of
enum-set1 and enum-set2.
(let* ((e (make-enumeration '(red green blue))) (c (enum-set-constructor e))) (list (enum-set->list (enum-set-union (c '(blue)) (c '(red)))) (enum-set->list (enum-set-intersection (c '(red green)) (c '(red blue)))) (enum-set->list (enum-set-difference (c '(red green)) (c '(red blue)))))) ⇒ ((red blue) (red) (green))
Return enum-set’s complement with respect to its universe.
(let* ((e (make-enumeration '(red green blue))) (c (enum-set-constructor e))) (enum-set->list (enum-set-complement (c '(red))))) ⇒ (green blue)
Project enum-set1 into the universe of enum-set2, dropping any elements of enum-set1 that do not belong to the universe of enum-set2. (If enum-set1 is a subset of the universe of enum-set2, no elements are dropped, and the injection is returned.)
(let ((e1 (make-enumeration '(red green blue black))) (e2 (make-enumeration '(red black white)))) (enum-set->list (enum-set-projection e1 e2)))) ⇒ (red black)
The define-enumeration
form defines an enumeration type and
provides two macros for constructing its members and sets of its
members.
A define-enumeration
form is a definition and can appear anywhere
any other ?definition can appear.
?type-name is an identifier that is bound as a syntactic keyword; ?symbol … are the symbols that comprise the universe of the enumeration (in order).
(?type-name ?symbol)
checks at macro-expansion time
whether the name of ?symbol is in the universe associated with
?type-name. If it is, (?type-name ?symbol)
is equivalent to ?symbol
. It is a syntax violation if it
is not.
?constructor-syntax is an identifier that is bound to a macro that, given any finite sequence of the symbols in the universe, possibly with duplicates, expands into an expression that evaluates to the enumeration set of those symbols.
(?constructor-syntax ?symbol ...)
checks at
macro-expansion time whether every ?symbol ... is in the universe
associated with ?type-name. It is a syntax violation if one or
more is not. Otherwise:
(?constructor-syntax ?symbol ...)
is equivalent to:
((enum-set-constructor (?constructor-syntax)) '(?symbol ...))
Example:
(define-enumeration color (black white purple maroon) color-set) (color black) ⇒ black (color purpel) ⇒ exception &syntax (enum-set->list (color-set)) ⇒ () (enum-set->list (color-set maroon white)) ⇒ (white maroon)
NOTE In the forms:
(?type-name ?symbol) (?constructor-syntax ?symbol ...)only the names of the ?symbols are significant.
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